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Language: C

Author: Guest

Comments: 0

Useful:

Code:

puts("You have many choices: \n"); puts("a) invert a number. b) bit and two numbers.\n"); puts("c) bit or two numbers. d)bit xor two numbers.\n"); puts("e) quit.\n"); puts("Plz enter your choice."); getchar(); while ((option = scanf("%c", &option)) == 1) { putchar(option); puts("abcdefg\n"); int choice = 1; switch(option) { case 'a': puts("Enter 1 or 2."); scanf("%d", &choice); if(choice == 1){ printf("~%d number is: %d\n", choice, binary_to_int(binary1));} if(choice == 2){ printf("~%d number is: %d\n", choice, binary_to_int(binary2));} else{ puts("Wrong number, go to next round now.\n");} break; case 'b': printf("Num 1 bit and Num 2 == %d.\n", binary_to_int(binary1) & binary_to_in

Details:

why press input just quit

Solution:

There are several issues in your code snippet that may be causing the problem. Here are some possible solutions:

1. When using `scanf` to read a character, the newline character from the previous input may still be in the input buffer. This can cause issues with reading further input. You can add an additional `getchar()` after the `scanf` to consume the newline character.

c
while ((option = getchar()) != '\n') {} // consume remaining characters in input buffer

2. The `scanf` function returns the number of successful conversions. You are comparing `option` with the return value of `scanf`, which may not be what you intend. Instead, you should read the input character using `scanf("%c", &option)` and then check if it matches the expected options.

3. The text-based menu system can be improved by providing a default case in the switch statement to handle invalid user input. This way, the user will be prompted to enter a valid option.

c
default:
    puts("Invalid option. Please enter a valid choice (a, b, c, d, or e).");

By making these changes, you should be able to handle user input more effectively and prevent unexpected termination.

"User-Choice Binary Operations Menu with Input Processing"